An air bubble of volume 1 cm 3 rises from the bottom of a lake 40 m deep to the surface at a temperature of 12 °C. The atmospheric pressure is 1 x 10 5 Pa, the density of water is 1000 kg m -3 and g = 10 m s -2 . There is no difference of the temperature of water at the depth of 40 m and on the surface. The volume of air bubble when it reaches the surface will be
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The pressure at the bottom of the lake can be calculated as follows:
= (10 5 + 1000 x 10 x 40) Pa
=5 x 10 5 Pa
As the temperature of water remains constant, it can be written that
P bottom V bottom = P top V top …
Substitute the values of the known parameters into equation to calculate the required volume of the bubble when it reaches the surface.
5x10 5 x1 = 1x10 5 xV top
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